Let the first odd integer be
N.
Then, the next consecutive integer is
(N+2).
Given that the sum of the integers is
116.
Then, we will write:
N +
(N+2)= 116
Now we will simplify and solve the
equation.
==> N+ N + 2 =
116
==> 2N + 2 =
116
Now we will solve for
N.
Subtract 2 from both
sides.
==> 2N = 116-2 =
114
==> 2N = 114
Now we
will divide by 2.
==> N =
57
Then, the next consecutive integer is 57+2 =
59.
Then, the integers are: 57 and
59
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