Thursday, June 25, 2015

What is the solution for c given that cot(4c - pi/4) + tan(2c + pi/4) = 0

We have to find the value of c such that cot(4c - pi/4) +
tan(2c + pi/4) = 0


cot(4c - pi/4) + tan(2c + pi/4) =
0


=> cos(4c - pi/4)/sin(4c - pi/4) + sin(2c +
pi/4)/cos(2c + pi/4) = 0


=> cos(4c - pi/4)cos(2c +
pi/4) + sin(2c + pi/4)sin(4c - pi/4) = 0


=> cos(4c -
pi/4 - 2c - pi/4) = 0


=> cos(2c - pi/2) =
0


=> sin 2c = 0


2c = 0
+ n*2pi and 2c = pi + n*2pi


=> c = n*pi and c = pi/2
+ n*pi


The values of c that satisfy the
equation are n*pi and pi/2 + n*pi

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