We are given sets and know
that:
1.
P_1
2.
P_2
3.
P_2
We must show that
P_2
(In English: show every everything in both S1 and S2
is also in both P1 and
P2)
Proof:
Let be an
element of . This implies that
and
. By (3), we also
know that either or
.
Case one:
suppose : By (2), we see
and
and by (2)
subset P_2x in P_2
Case two: suppose
in P_2 x in S_1
P_2 nn S_1 subset P_1
x in P_1
.
Since each of these cases shows x must exist in both P1
and P2, it follows that
No comments:
Post a Comment