How much heat would be required to warm oceans by 1.0 degree celcius. V of ocean water 137 x 10 ^7 km ^3 and the density of seawater is...

We calculate temperature change due to heat transfer with
this equation:

Q = m x c x delta
T

Where  Q stands for the enegry transferred, m is the mass
of the material, c is the specific heat capacity of the material, and delta T is the
change in temperature.

In this case, c = 4.186 joules per
gram per degree C

Delta T =
1

We need to calculate the mass of the oceans in grams for
m

1 Km = 1 x 10^5 cm; we cube this to
get:

1 Km^3 = 1 x 10^15
cm^3

Then we can do the conversion
-

137 x 10^7  Km^3   x    1 x 10^15 cm^3/1 Km^3 = 
1.37x10^24

Now, back to Q = m X c X delta
T

Q = 1.37x10^24 x 4.186 x 1

Q
= 5.735x10^24 Joules