You need to determine all functions which are in the
relation f(x)*f(y) = f(x)+f(y)+xy-1
Put x=y=1 =>
f(1)*f(1) = f(1)+f(1)+1-1 => `f^2(1) =
2f(1)`
Subtract 2f(1) and then factor
f(1):
`f^2(1) -2f(1) = 0` => `f(1)*(f(1) - 2) = 0`
=> f(1)=0
f(1) - 2 = 0 => f(1) =
2
Put f(1) = 0 => if y = 1 and x `in` R, then the
relation f(x)*f(y) = f(x)+f(y)+xy-1 suffers a
transformation.
f(x)*f(1) =
f(x)+f(1)+x-1
0 = f(x)+0+x-1 => f(x) =
1-x
If f(1) = 2 => y=1, x `in`
R
2f(x) = f(x)+2+x-1
Subtract
f(x)=> f(x) = x + 1
ANSWER: The
functions that check the relation f(x)*f(y) = f(x)+f(y)+xy-1 are f(x) = 1-x and f(x) = x
+ 1.
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