Friday, November 6, 2015

Solve 2^2x -12*2^x + 32 = 0

We have to solve: 2^2x -12*2^x + 32 =
0


2^2x -12*2^x + 32 = 0


Let
2^x = y


=> y^2 - 12y + 32 =
0


=> y^2 - 8x - 4x + 32 =
0


=> y(y - 8) - 4(y - 8) =
0


=> (y - 4)(y - 8) =
0


=> y = 4 and y = 8


As
2^x = y


2^x = 4


=> x =
2


and 2^x = 8


=> x =
3


The solution of the given equation is x = 2
and x = 3

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