solve this exponetial equation: (1/25)^(-x^2+5x-8)a^g(x) if a

indeed:

class="AM">`(1/25)^(-x^2+5x-8)< (1/25)^(-2)`                   
(1)

Your friend, according me, did trick
himself.

Indeed, even  if (1)
implies:

`-2<
-x^2+5x-8`  for class="AM">`(1/25)<1`

that is:  
`-x^2+5x-6>0`

On
the other side you can write (1) as:

class="AM">`1/25^(-x^2+5x-8)<
1/25^-2`

class="AM">`1/25^(-(x^2-5x+8)) <
1/25^(-2)`

class="AM">`25^(-(-(x^2-5x+8)))<25^(-(-2))`

class="AM">`25^(x^2-5x+8)<25^2`

class="AM">`x^2-5x+8<2`

class="AM">`x^2-5x+6<0`

that is
:

class="AM">`-x^2+5x-6>0`

So:
WHATEVER WAY YOU CHOICE THE RESLULT IS TO BE THE
SAME!

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