perimeter of a rectangle is 44cm if the rectangle is divided into 5 congurent rectangle find the measure of each rectangles plz draw figure

Given that the perimeter of a rectangle is 44cm,
and that the rectangle is divided into 5 congruent rectangls, find the measure of each
of the rectangles.

There is not enough
information given to give a unique answer. Let the length be given by 5a, so the width
is (22-5a). Note that 5a+(22-5a)+5a+(22-5a)=44=the perimeter. Then each of the
subdivided rectangles has dimensions l by (22-5a). e.g. for a=1 you have the large
rectangle with dimension 5x17, and each small rectangle with dimensions 1x17; if a=2 you
have the large rectangle with dimensions 6x16, and each small rectangle with dimensions
6/5x16.

a  a  a   a   a total
length=5a
---------------
|   |   |   |   |   |       width =
22-5a
---------------

If you are also given
another constraint, for instance the area of either the large rectangle or one of the
subdivided rectangles, or are asked to find the largest such rectangle by area, then you
could give a unique singular answer.

As the question is
stated, let the length be 5a, then the widthis (22-5a) and each of the small rectangles
has dimensions ax(22-5a).

*(The area of the large rectangle
is 5a*(22-5a) and the area of each small rectangle is a*(22-5a).