Let us assume that the quadratic function is f(x) such
that:
Given the points: (2, 6) ( -2, -2) and (1,1).
Since the
points are on the graph, then they satisfy the
equation.
Then we will substitute with each point in
f(x).
.......(1)
............(2)
C
................(3)
Now we will solve the
system.
First we will subtract (2) from
(1).
==> 4b = 8 ==> b=
2
Now we will subtract (3) from
(2).
==> 3a -3b =
-3
==> a - b= -1
But b=
2
==> a - 2 = -1 ==> a =
1
==> a+ b+ c =
1
==> 1 +2 + C =
2
==> C = -2
Then the
function is:
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